45x^2-88x+35=0

Solution for 45x^2-88x+35=0 equation:

45x^2-88x+35=0

a = 45; b = -88; c = +35;
Δ = b2-4ac
Δ = -882-4·45·35
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-38}{2*45}=\frac{50}{90}
=5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+38}{2*45}=\frac{126}{90}
=1+2/5
$